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$\mathrm{Cl}-\mathrm{P}-\mathrm{Cl}$ bond angles in $\mathrm{PCl}_{5}$ molecule are
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$120^{\circ}$ and $90^{\circ}$
In $\mathrm{PCl}_{5}$, phosphorous undergoes $\mathrm{sp}^{3} \mathrm{~d}$ hybridization and has trigonal bipyramidal geometry. It has two axial chlorine atoms \& three equatorial chlorine atoms bonded to the central P.
Hence bond angles for axial are $90^{\circ}, \mathrm{Cl}-\mathrm{P}-\mathrm{Cl}$ \& for equatorial Cl-P-Cl it is $120^{\circ}$.
Hence bond angles for axial are $90^{\circ}, \mathrm{Cl}-\mathrm{P}-\mathrm{Cl}$ \& for equatorial Cl-P-Cl it is $120^{\circ}$.
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