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Question: Answered & Verified by Expert
$\mathrm{CO}_{2}$ is passed through lime water. Initially the solution tums milky and then becomes clear upon continued boubbling of $\mathrm{CO}_{2}$. The clear solution is due to the formation of
Chemistrys Block ElementsKVPYKVPY 2017 (5 Nov SA)
Options:
  • A $\mathrm{CaCO}_{3}$
  • B $\mathrm{CaO}$
  • C $\mathrm{Ca}(\mathrm{OH})_{2}^{2}$
  • D $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}$
Solution:
1997 Upvotes Verified Answer
The correct answer is: $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}$
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{CO}_{2} \longrightarrow \mathrm{CaCO}_{3}+\mathrm{H}_{2} \mathrm{O}$ $\mathrm{CaCO}_{3}+\mathrm{H}_{2} \mathrm{O} \underset{\longrightarrow}{\mathrm{CO}_{2}}{\longrightarrow} \mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}$ $\quad$ Clear solution

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