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Compound $\mathrm{A}$ on reaction with chlorine in presence of u.v. light gives $\mathrm{B} ;$ which when reacted with $\mathrm{NaNO}_{2}$ in the solvent $\mathrm{N}, \mathrm{N}$ -dimethyl formamide, gives 2 -Nitrobutane. The compound $\mathrm{A}$ is
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$A+Cl_{2} / h r \longrightarrow B$

$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3} ; \quad \mathrm{B}=$

$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3} ; \quad \mathrm{B}=$

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