Compound ‘A’ with molecular formula C 4 H 9 Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both. Out of these two compounds, which one will be converted to the product with inverted configuration?

Question

Compound ‘A’ with molecular formula C 4 H 9 Br is treated with aq. KOH solution. The rate of this reaction depends upon the concentration of the compound ‘A’ only. When another optically active isomer ‘B’ of this compound was treated with aq. KOH solution, the rate of reaction was found to be dependent on concentration of compound and KOH both. Out of these two compounds, which one will be converted to the product with inverted configuration?, Both Compound ‘A’ and ’B’ will be converted to the product with inverted configuration, Neither Compound ‘A’ nor ‘B’ will be converted to the product with inverted configuration, Compound ‘A’ will be converted to the product with inverted configuration, Compound ‘B’ will be converted to the product with inverted configuration

MARKS App · Accepted Answer

Correct Option is : (D) Compound ‘B’ will be converted to the product with inverted configuration

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