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Conductivity of a solution is $1.26 \times 10^{-2} \Omega^{-1} \mathrm{~cm}^{-1}$. Calculate molar conductivity for $0.01 \mathrm{M}$ solution.
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The correct answer is:
$1.26 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$
$\begin{aligned} \Lambda & =\frac{1000 \mathrm{k}}{\mathrm{c}} \\ & =\frac{1000 \mathrm{~cm}^3 \mathrm{~L}^{-1} \times 1.26 \times 10^{-2} \Omega^{-1} \mathrm{~cm}^{-1}}{0.01 \mathrm{~mol} \mathrm{~L}^{-1}} \\ & =1.26 \times 10^3 \Omega^{-1} \mathrm{~cm}^2 \mathrm{~mol}^{-1}\end{aligned}$
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