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Question: Answered & Verified by Expert
Consider a nucleus X3060. It's approximate density is (Take 1 amu=1.6×10-27 kg,Ro=1.2×10-15 m)
PhysicsNuclear PhysicsJEE Main
Options:
  • A 1.2×1018 kg m-3
  • B 8.5×1019 kg m-3
  • C 3.3×1016 kg m-3
  • D 2.2×1017 kg m-3
Solution:
1022 Upvotes Verified Answer
The correct answer is: 2.2×1017 kg m-3

Density=massvolume

=A×1.6×10-274π3×R0A133=34π×1.6×10-271.2×10-153=2.2×1017 kg m-3

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