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Question: Answered & Verified by Expert
Consider a reaction X + Y Products. If the initial concentration of X is increased to four times of its original value, keeping the concentration of Y constant, the rate of reaction increases four-fold. When the concentration of both X and Y becomes four times their original values, the rate of reaction becomes 16 times its original value. The observed rate law is
ChemistryChemical KineticsNEET
Options:
  • A k[X]2[Y]2
  • B k[X]1[Y]2
  • C k[X]1[Y]1
  • D k[X]2[Y]1
Solution:
2340 Upvotes Verified Answer
The correct answer is: k[X]1[Y]1
r1=k[X]m[Y]n …(i)
r2=4r1=k[4X]m[Y]n …(ii)
r3=16r1=k[4X]m[4Y]n …(iii)
Divide equation (ii) by equation (i)
4=(4)m
(4)1=(4)m
m=1
Divide equation (iii) by equation (ii),
4=(4)n
(4)1=(4)n
n=1 .
Hence rate =k[X]1[Y]1

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