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Consider a uniform square plate of side ' $a$ ' and mass ' $m$ '. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is
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Verified Answer
The correct answer is:
$\frac{2}{3} m a^2$
$\frac{2}{3} m a^2$
$$
I=I_{c m}+m\left(\frac{a \sqrt{2}}{2}\right)^2=\frac{m a^2}{6}+\frac{m a^2}{2}=\frac{2}{3} m a^2
$$
I=I_{c m}+m\left(\frac{a \sqrt{2}}{2}\right)^2=\frac{m a^2}{6}+\frac{m a^2}{2}=\frac{2}{3} m a^2
$$
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