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Consider an endothermic reaction $X \rightarrow Y$ with the activation energies $E_b$ and $E_f$ for the backward and forward reactions, respectively, in general
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The correct answer is:
$E_b \lt E_f$
For endothermic reaction $\Delta H=+v e$
Then from equation $\Delta H=E_{a_{F, R .}}-E_{a_{B, R}} ; E_{B . R .} \lt E_{F . R}$.
Then from equation $\Delta H=E_{a_{F, R .}}-E_{a_{B, R}} ; E_{B . R .} \lt E_{F . R}$.
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