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Consider the figure provided.
\(1 \mathrm{~mol}\) of an ideal gas is kept in a cylinder, fitted with a piston, at the position A, at \(18^{\circ} \mathrm{C}\). If the piston is moved to position \(\mathrm{B}\), keeping the temperature unchanged, then ' \(x\) ' \(L\) atm work is done in this reversible process.
\(x=\) ______ \(\mathrm{L}\) atm. (nearest integer)
[Given : Absolute temperature \(={ }^{\circ} \mathrm{C}+273.15, \mathrm{R}=0.08206 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}{ }^{-1} \mathrm{~K}^{-1}\) ]
Solution:
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Verified Answer
The correct answer is:
55
$\begin{aligned} & \omega=-n R T \ln \left(\frac{V_2}{V_1}\right) \\ & =-1 \times \cdot 08206 \times 291 \cdot 15 \ln \left(\frac{100}{10}\right) \\ & =-55.0128\end{aligned}$
Work done by system $\approx 55 \mathrm{~atm}$ lit.
Work done by system $\approx 55 \mathrm{~atm}$ lit.
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