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Consider the following
(I) The order of first ionisation enthalpy of first three elements of $3^{\text {rd }}$ period is $\mathrm{Mg}>\mathrm{Al}>\mathrm{Na}$
(II) The element with electronegativity of 3.5 is chlorine
(III) The order of sizes of ions $\mathrm{Mg}^{2+}, \mathrm{Na}^{+}, \mathrm{F}^{-}$and $\mathrm{O}^{2-}$ is $\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}$
(IV)The IUPAC name of the element with atomic number 106 is Bohrium.
The correct statements are
Options:
(I) The order of first ionisation enthalpy of first three elements of $3^{\text {rd }}$ period is $\mathrm{Mg}>\mathrm{Al}>\mathrm{Na}$
(II) The element with electronegativity of 3.5 is chlorine
(III) The order of sizes of ions $\mathrm{Mg}^{2+}, \mathrm{Na}^{+}, \mathrm{F}^{-}$and $\mathrm{O}^{2-}$ is $\mathrm{Mg}^{2+} < \mathrm{Na}^{+} < \mathrm{F}^{-} < \mathrm{O}^{2-}$
(IV)The IUPAC name of the element with atomic number 106 is Bohrium.
The correct statements are
Solution:
2218 Upvotes
Verified Answer
The correct answer is:
I & III only
Statement (II) is incorrect as oxygen is the element with an electronegativity of 3.5 and not chlorine.
Statement (IV) is incorrect as the element with the atomic number 106 is seaborgium ( $\mathrm{Sg}$ ) and not Bohrium (Bh)
Statement (IV) is incorrect as the element with the atomic number 106 is seaborgium ( $\mathrm{Sg}$ ) and not Bohrium (Bh)
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