Considering that Δ 0 > P , the magnetic moment (in BM) of Ru H 2 O 6 2 + would be

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Question: Answered & Verified by Expert

Considering that

Δ_{0} > P

, the magnetic moment (in BM) of

{[Ru {(H_{2} O)}_{6}]}^{2 +}

would be

ChemistryCoordination CompoundsJEE MainJEE Main 2020 (05 Sep Shift 2)

Solution:

1263 Upvotes Verified Answer

The correct answer is: 0

{Ru}^{2 *} = 4 d^{6} = t 2 g^{2, 2.2} {eg}^{0, 0}

since

Δ_{0} > P

No. of unpaired electrons = zero
Magnetic Moment

= 0

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