Excess of NaOH reacts with Zn to form, ZnH 2 , Na 2 ZnO 2 , ZnO, Zn ( OH ) 2

Zn + 2 NaOH → Na 2 ZnO 2 + H 2 Sod. zincate

Excess of NaOH reacts with Zn to form

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Excess of NaOH reacts with $\mathrm{Zn}$ to form

Chemistrys Block ElementsVITEEEVITEEE 2006

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Solution:

2563 Upvotes Verified Answer

The correct answer is: $\mathrm{Zn}(\mathrm{OH})_{2}$

$\mathrm{Zn}+2 \mathrm{NaOH} \rightarrow \mathrm{Na}_{2} \mathrm{ZnO}_{2}+\mathrm{H}_{2}$
$\quad\quad\quad\quad\quad\quad$ Sod. zincate

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