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Figure shows a long straight wire of a circular cross-section (radius a) carrying steady current I. The current I is uniformly distributed across this cross-section. Calculate the magnetic field in the region r > a

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The correct answer is:
$B~=~\left( \frac{{{\mu }_{0}}I}{2\pi {{a}^{2}}} \right)r$
Correct Option is : (C)
$B~=~\left( \frac{{{\mu }_{0}}I}{2\pi {{a}^{2}}} \right)r$
$B~=~\left( \frac{{{\mu }_{0}}I}{2\pi {{a}^{2}}} \right)r$
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