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How do you explain the presence of five —OH groups in glucose molecules?
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The correct answer is:
Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.
Correct Option is : (C)
Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.
Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.
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