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Question: Answered & Verified by Expert
How do you explain the presence of five —OH groups in glucose molecules?
ChemistryBiomoleculesNEET
Options:
  • A Glucose reacts with hydroxylamine to form an oxime
  • B On oxidation with nitric acid, glucose as well as gluconic acid both yield a dicarboxylic acid, saccharic acid
  • C Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.
  • D On prolonged heating with HI, it forms n-hexane
Solution:
2554 Upvotes Verified Answer
The correct answer is: Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.
Correct Option is : (C)
Glucose gives pentaacetate derivative on acetylation with acetic anhydride. This confirms the presence of five —OH groups.

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