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If 4 moles of an ideal monoatomic gas at temperature $400 \mathrm{~K}$ is mixed with 2 moles of another ideal monoatomic gas at temperature $700 \mathrm{~K}$, the temperature of the mixture is
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The correct answer is:
$500 \mathrm{~K}$
Temperature of the mixture
$$
\begin{aligned}
T & =\frac{m_1 T_1+m_2 T_2}{m_1+m_2} \\
& =\frac{4(400)+2(700)}{4+2}=500 \mathrm{~K}
\end{aligned}
$$
$$
\begin{aligned}
T & =\frac{m_1 T_1+m_2 T_2}{m_1+m_2} \\
& =\frac{4(400)+2(700)}{4+2}=500 \mathrm{~K}
\end{aligned}
$$
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