If A = 0 − 1 2 1 0 − 5 − 2 5 0 , then, A ′ = A, A ′ = − A, A ′ = 2 A, None of these

A ′ = 0 1 − 2 − 1 0 5 2 − 5 0 = − A

If A = 0 − 1 2 1 0 − 5 − 2 5 0 , then

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If $A=\left[\begin{array}{ccc}0 & 1 & -2 \\ -1 & 0 & 5 \\ 2 & -5 & 0\end{array}\right]$, then

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Solution:

1132 Upvotes Verified Answer

The correct answer is: $A^{\prime}=-A$

$A^{\prime}=\left[\begin{array}{ccc}0 & -1 & 2 \\ 1 & 0 & -5 \\ -2 & 5 & 0\end{array}\right]=-A$

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