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If a change in current of $0.01 \mathrm{~A}$ in one coil produces a change in magnetic flux of $2 \times 10^{-2}$ Wb in the other coil, then the mutual inductance of the two coils in henry is
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$20 \mathrm{~T}$
$\begin{aligned} & \Delta i=0.01 \mathrm{~A}, \Delta \phi=2 \times 10^{-2} \mathrm{~Wb} \\ & \text { Mutual inductance } M=\frac{\Delta \phi}{\Delta i} \\ & =\frac{2 \times 10^{-2}}{0.01}=\frac{2 \times 10^{-2}}{10^{-3}} \\ & =2 \mathrm{H}\end{aligned}$
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