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If a die is rolled three times, then the probability of getting a larger number on its face than the previous number each time, is
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Verified Answer
The correct answer is:
$\frac{5}{54}$
Here, total number of possible out come
$$
=6^3=216
$$
Now, we can choose any three numbers out of 6 numbers and we can place them in ascending order and we can place them in ascending order in only one way.
So, favourable out come $={ }^6 C_3=20$
Now, required probability $=\frac{20}{216}=\frac{5}{54}$
$$
=6^3=216
$$
Now, we can choose any three numbers out of 6 numbers and we can place them in ascending order and we can place them in ascending order in only one way.
So, favourable out come $={ }^6 C_3=20$
Now, required probability $=\frac{20}{216}=\frac{5}{54}$
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