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If a Young's double slit experiment, if the distance between
two slits is reduced by a factor of 2 and the wavelength of
light is increased 4 times then the distance between two
maxima will become _____ times the original value.
Options:
two slits is reduced by a factor of 2 and the wavelength of
light is increased 4 times then the distance between two
maxima will become _____ times the original value.
Solution:
1931 Upvotes
Verified Answer
The correct answer is:
8
$$
\begin{aligned}
& \text { } \beta=- \\
& \Rightarrow \beta \propto \frac{\lambda}{\mathrm{d}} \\
& \Rightarrow \frac{\beta_1}{\beta_2}=\frac{\lambda_1}{\lambda_2} \times \frac{\mathrm{d}_2}{\mathrm{~d}_1}=\frac{1}{4} \times \frac{1}{2}=\frac{1}{8} \Rightarrow \beta_2=8 \beta_1
\end{aligned}
$$
\begin{aligned}
& \text { } \beta=- \\
& \Rightarrow \beta \propto \frac{\lambda}{\mathrm{d}} \\
& \Rightarrow \frac{\beta_1}{\beta_2}=\frac{\lambda_1}{\lambda_2} \times \frac{\mathrm{d}_2}{\mathrm{~d}_1}=\frac{1}{4} \times \frac{1}{2}=\frac{1}{8} \Rightarrow \beta_2=8 \beta_1
\end{aligned}
$$
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