If an endothermic reaction is non-spontaneous at freezing of water and becomes feasible at its boiling point, then

Question

If an endothermic reaction is non-spontaneous at freezing of water and becomes feasible at its boiling point, then, Δ H is –ve, Δ S is +ve, Δ H and Δ S both are +ve, Δ H and Δ S both are -ve, Δ H is +ve, Δ S is -ve

MARKS App · Accepted Answer

Δ G = Δ H - T Δ S , since Δ G = + v e at T = 273 K and Δ H = + v e and at high temperature 373 K, it becomes spontaneous ( Δ G = - v e ) even if Δ H = + v e . This is possible only, if Δ S = + v e because at high temperature T Δ S > Δ H to give Δ G = - v e .

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