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If collector current is \(120 \mathrm{~mA}\) and base current is \(2 \mathrm{~mA}\) and resistance gain is 3 , what is power gain?
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Verified Answer
The correct answer is:
10800
Current gain \(\beta=\frac{I_C}{I_B}=\frac{(120 \mathrm{~mA})}{(2 \mathrm{~mA})}=60\)
Power gain \(=\) Resistance gain \(\times \beta^2\)
\(=(3) \times(60)^2=10800\)
Power gain \(=\) Resistance gain \(\times \beta^2\)
\(=(3) \times(60)^2=10800\)
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