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Question: Answered & Verified by Expert
If f1=1,f'1=3, then the derivative of fffx+fx2 at x=1 is:
MathematicsDifferentiationJEE MainJEE Main 2019 (08 Apr Shift 2)
Options:
  • A 9
  • B 12
  • C 15
  • D 33
Solution:
1329 Upvotes Verified Answer
The correct answer is: 33
y=fffx+fx2

dydx=f'ffx×f'fx×f'x+2fx×f'x

dydxx=1=f'ff1×f'f1×f'1+2f1×f'1

=f'f1×f'1×3+2×1×3

=f'1×3×3+6

=3×3×3+6

=27+6

=33

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