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If $f$ is linear function and $f(2)=4, f(-1)$ $=3$, then find $f(x)$.
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Verified Answer
The correct answer is:
$f(x)=\frac{x+10}{3}$
Let linear function is $f(x)=\mathrm{ax}+\mathrm{b}$
Given $f(2)=4 \Rightarrow 2 a+b=4$
Also $f(-1)=3 \Rightarrow-a+b=3$
Solving (1) and (2) we get $a=\frac{1}{3}$ and $b=\frac{10}{3}$
Hence, $f(x)=\frac{x+10}{3}$
Given $f(2)=4 \Rightarrow 2 a+b=4$
Also $f(-1)=3 \Rightarrow-a+b=3$
Solving (1) and (2) we get $a=\frac{1}{3}$ and $b=\frac{10}{3}$
Hence, $f(x)=\frac{x+10}{3}$
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