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If $f: R \rightarrow R$ is defined by $f(x)=|x|$, then
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Verified Answer
The correct answer is:
the function $f^{-1}(x)$ does not exist
We have, $f(x)=|x|$
$$
f(x)= \begin{cases}x, & \text { if } x \geq 0 \\ -x, & \text { if } x \leq 0\end{cases}
$$
So, the function $f^{-1}(x)$ does not exist.
$$
f(x)= \begin{cases}x, & \text { if } x \geq 0 \\ -x, & \text { if } x \leq 0\end{cases}
$$
So, the function $f^{-1}(x)$ does not exist.
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