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If $f: R \rightarrow R$ is defined by $f(x)=|x|$, then
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Verified Answer
The correct answer is:
The function $f^{-1}(x)$ does not exist.
Since, $f(x)=|x|$ is neither one-one nor onto, 30 $f(x)$ is not invertible.
$\therefore f^{-1}(x)$ does not exist.
$\therefore f^{-1}(x)$ does not exist.
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