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Question: Answered & Verified by Expert
If $f: R \rightarrow R$ is given by $f(x)=7 x+8$ and $f^{-1}(12)=\frac{k}{7}$, then the value of $k$ is
MathematicsFunctionsMHT CETMHT CET 2020 (19 Oct Shift 1)
Options:
  • A 7
  • B 1
  • C 4
  • D 8
Solution:
1259 Upvotes Verified Answer
The correct answer is: 4
(C)
We have $f(x)=7 x+8=y$...(let)
$\therefore \mathrm{x}=\frac{\mathrm{y}-8}{7} \Rightarrow \mathrm{f}^{-1}(\mathrm{y})=\frac{\mathrm{y}-8}{7}$ $\therefore \mathrm{f}^{-1}(\mathrm{x})=\frac{\mathrm{x}-8}{7} \Rightarrow \mathrm{f}^{-1}(12)=\frac{12-8}{7}=\frac{4}{7} \Rightarrow \mathrm{k}=4$

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