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Question: Answered & Verified by Expert
If fx=-2sinxπx3π2pcosx+q3π2<x<2πcosx-22πx5π2rsinx5π2<x3π is continuous in π,3π, then the number of points at which fx is not differentiable is/are
MathematicsContinuity and DifferentiabilityJEE Main
Solution:
2529 Upvotes Verified Answer
The correct answer is: 2
At 3π2, -2-1=p0+qq=2
At 2π, p+q=1-2p=3
At 5π2, 0-2=r1r=-2
f'x=-2cosx;  πx<3π2ND;  x=3π23sinx;  3π2<x<2π0;  x=2π-sinx;  2π<x<5π2ND;  x=5π2<x<3π-2cosx;  5π2<x<3π
fx is not differentiable at 3π2 & 5π2

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