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If $\mathrm{I}_1=\int_0^{3 \pi} \mathrm{f}\left(\cos ^2 \mathrm{x}\right) \mathrm{dx}$ and $\mathrm{I}_2=\int_0^\pi \mathrm{f}\left(\cos ^2 \mathrm{x}\right) \mathrm{dx}$, then
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The correct answer is:
$\mathrm{I}_1=3 \mathrm{I}_2$
Hints : $I_1=3 \int_0^\pi \mathrm{f}\left(\cos ^2 x\right) d x=3 I \quad$ [period is $\pi$ ]
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