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Question: Answered & Verified by Expert
If ' $l$ ' is the length of the open pipe, ' $r$ ' is the internal radius of the pipe and ' $V$ ' is the velocity of sound in air then fundamental frequency of open pipe is
PhysicsWaves and SoundMHT CETMHT CET 2023 (14 May Shift 1)
Options:
  • A $\frac{\mathrm{V}}{(l+0.3 \mathrm{r})}$
  • B $\frac{\mathrm{V}}{(l+1.2 \mathrm{r})}$
  • C $\frac{\mathrm{V}}{(l+0.6 \mathrm{r})}$
  • D $\frac{\mathrm{V}}{2(l+1.2 \mathrm{r})}$
Solution:
2990 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{V}}{2(l+1.2 \mathrm{r})}$
For an open organ pipe, the length of the pipe with end correction is given as:
$$
\begin{aligned}
& \mathrm{L}=l+2 \mathrm{e}=l+2 \times 0.6 \mathrm{r} \\
& \mathrm{L}=l+1.2 \mathrm{r}
\end{aligned}
$$
$\therefore \quad$ The fundamental frequency of open pipe is:
$$
\begin{aligned}
& \mathrm{f}=\frac{\mathrm{v}}{2 \mathrm{~L}} \\
& \mathrm{f}=\frac{\mathrm{v}}{2(l+1.2 \mathrm{r})}
\end{aligned}
$$

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