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If $\lim _{x \rightarrow 1} \frac{x^2-a x+b}{(x-1)}=5$, then $(a+b)$ is equal to
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The correct answer is:
$-7$

Applying $\Rightarrow a=-3$ Hospital's rule
$\begin{aligned} & \Rightarrow 2 \times 1-a=5 \\ & \Rightarrow a=-3\end{aligned}$
from (1) $b=-4$
$\Rightarrow a+b=-7$
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