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If $M_{O}$ is the mass of an oxygen isotope ${ }_{8} \mathrm{O}^{17}$, $M_{p}$ and $M_{n}$ are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is
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Verified Answer
The correct answer is:
$\left(M_{O}-8 M_{p}-9 M_{n}\right) c^{2}$
Binding energy
$$
\begin{aligned}
\mathrm{BE} &=\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) c^{2} \\
&=\left(M_{O}-8 M_{p}-9 M_{n}\right) c^{2}
\end{aligned}
$$
$$
\begin{aligned}
\mathrm{BE} &=\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) c^{2} \\
&=\left(M_{O}-8 M_{p}-9 M_{n}\right) c^{2}
\end{aligned}
$$
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