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If $M_o$ is the mass of isotope ${ }_5^{12} B, M_P$ and $M_n$ are the masses of proton and neutron, then nuclear binding energy of isotope is :
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The correct answer is:
$\left(5 M_p+7 M_n-M_o\right) C^2$
$\begin{aligned} & \text { B.E. }=\Delta m C^2 \\ & \left(5 M_p+7 M_n-M_o\right) C^2\end{aligned}$
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