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If $N$ is a set of natural numbers, then under binary operation $a \cdot b=a+b,(\mathrm{~N}, \cdot)$ is
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The correct answer is:
semi-group
The structure $(\mathrm{N}, .)$ satisfies the closure property, associativity and commutativity but the identity element 0 does not belong to $\mathrm{N}$.
So, $N$ is a semi-group.
So, $N$ is a semi-group.
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