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If one side of an isosceles triangle is given by $y=2$ and the base is provided by the points $(2,0)$ and $(0,2)$, then its area (in sq. units) is
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$2$
$O A B C$ is a square.
$\therefore$ Required area $=\frac{1}{2} \times$ Area of $O A B C$
$=\frac{1}{2} \times(2)^2=2$ unit $^2$
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