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If $\sin \theta+\operatorname{cosec} \theta=2$, then the value of $\sin ^{10} \theta+\operatorname{cosec}^{10} \theta$ is equal to
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$2$
Given, $\sin \theta+\operatorname{cosec} \theta=2$
It is possible only $\sin \theta=\operatorname{cosec} \theta=1$
$\therefore \sin ^{10} \theta+\operatorname{cosec}^{10} \theta=(1)^{10}+(1)^{10}=1+1=2$
It is possible only $\sin \theta=\operatorname{cosec} \theta=1$
$\therefore \sin ^{10} \theta+\operatorname{cosec}^{10} \theta=(1)^{10}+(1)^{10}=1+1=2$
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