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If $\tan \theta=\frac{1}{3}$, then $\cos 2 \theta=$
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The correct answer is:
$\frac{4}{5}$
$\cos 2 \theta=\frac{1-\tan ^{2} \theta}{1+\tan ^{2} \theta}=\frac{\left(1-\frac{1}{9}\right)}{\left(1+\frac{1}{9}\right)}=\frac{4}{5}$
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