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If the binding energy per nuclear in $\mathrm{Li}^{7}$ and $\mathrm{He}^{4}$ nuclei are respectively $5.60 \mathrm{MeV}$ and $7.06 \mathrm{MeV}$, then energy of reactor $\mathrm{Li}^{7}+\mathrm{P} \rightarrow 2{ }_{2} \mathrm{He}^{4}$ is
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$17.3 \mathrm{MeV}$
$\mathrm{BE}$ of $\mathrm{Li}^{7}=39.20 \mathrm{MeV}$ and $\mathrm{He}^{4}=28.24 \mathrm{MeV}$
Hence binding energy of ${ }_{2} \mathrm{He}^{4}=56.84 \mathrm{MeV}$
Energy of reaction $=56.84-39.20$ $=17.28 \mathrm{MeV}$
Hence binding energy of ${ }_{2} \mathrm{He}^{4}=56.84 \mathrm{MeV}$
Energy of reaction $=56.84-39.20$ $=17.28 \mathrm{MeV}$
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