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If the circles $x^2+y^2=a^2$ and $x^2+y^2-2 g x+g^2-b^2=0$ touch each other externally, then
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The correct answer is:
$g=a+b$
According to the condition, $\sqrt{(g-0)^2+(0-0)^2}=a+b \Rightarrow g=a+b$
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