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Question: Answered & Verified by Expert
If the conductivity of $0.08 \mathrm{M}$ KCl solution is $2 \times 10^{-2} \Omega^{-1}$, what is the molar conductivity of the solution?
ChemistryElectrochemistryMHT CETMHT CET 2020 (14 Oct Shift 2)
Options:
  • A 350 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • B 250 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • C 25.0 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
  • D 0.25 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
Solution:
1619 Upvotes Verified Answer
The correct answer is: 250 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
$\Lambda=\frac{1000 \mathrm{k}}{\mathrm{C}}=\frac{1000 \times 2 \times 10^{-2}}{0.08}=250 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$

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