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If the conductivity of $0.08 \mathrm{M}$ KCl solution is $2 \times 10^{-2} \Omega^{-1}$, what is the molar conductivity of the solution?
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250 $\Omega^{-1} \mathrm{Cm}^{2} \mathrm{mol}^{-1}$
$\Lambda=\frac{1000 \mathrm{k}}{\mathrm{C}}=\frac{1000 \times 2 \times 10^{-2}}{0.08}=250 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$
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