Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the constant term in the binomial expansion of x-kx210 is 405, then k equals :
MathematicsBinomial TheoremJEE MainJEE Main 2020 (06 Sep Shift 2)
Options:
  • A 9
  • B 1
  • C 3
  • D 2
Solution:
2733 Upvotes Verified Answer
The correct answer is: 3

Tr+1=Cr10-kx2rx10-r

=Cr·10-kr·x5-5r2

for constant term

5-5r2=0  r=2

T3=C210·k2=405

10(9)2k2=405

k2=9

k=3

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.