If the de Broglie wavelength of an electron is equal to 10 - 3 times the wavelength of a photon of frequency 6 × 10 14 Hz , then the speed of the electron is equal to (Speed of light = 3 × 10 8 m s - 1 , Planck's constant = 6.63 × 10 - 34 J s , Mass of electron = 9.1 × 10 - 31 kg )

Question

If the de Broglie wavelength of an electron is equal to 10 - 3 times the wavelength of a photon of frequency 6 × 10 14 Hz , then the speed of the electron is equal to (Speed of light = 3 × 10 8 m s - 1 , Planck's constant = 6.63 × 10 - 34 J s , Mass of electron = 9.1 × 10 - 31 kg ), 1.45 × 10 6 m s - 1, 1.1 × 10 6 m s - 1, 1.7 × 10 6 m s - 1, 1.8 × 10 6 m s - 1

MARKS App · Accepted Answer

λ e = 10 - 3 λ p f p = 6 × 10 14 Hz = C λ p λ p = 3 × 10 8 6 × 10 14 = 0.5 × 10 - 6 m λ e = 0.5 × 10 - 9 = h m e v e v e = 6.63 × 10 - 34 9.1 × 10 - 31 × 0.5 × 10 - 9 = 1.45 × 10 6 m s - 1

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