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Question: Answered & Verified by Expert
If the de Broglie wavelength of electron is $728.14 \mathrm{~nm}$, its kinetic energy in $\mathrm{J}$ is: (mass of electron $=9.1 \times 10^{-31} \mathrm{~kg} ; \mathrm{h}=6.626 \times 10^{-34} \mathrm{~J} \mathrm{~s}$)
ChemistryStructure of AtomAP EAMCETAP EAMCET 2017 (25 Apr Shift 2)
Options:
  • A $4.55 \times 10^{-25}$
  • B $9.1 \times 10^{-25}$
  • C $4.55 \times 10^{-23}$
  • D $9.1 \times 10^{-23}$
Solution:
2414 Upvotes Verified Answer
The correct answer is: $4.55 \times 10^{-25}$
No solution. Refer to answer key.

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