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If the earth shrinks in its size (radius) mass remaining the same, the value of $g$ on its surface will
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Verified Answer
The correct answer is:
increase
The acceleration due to gravity at earth's surface is given by
$g=\frac{G M}{R^{2}}$
As, mass remains constant.
$\Rightarrow \quad g \propto \frac{1}{R^{2}}$
so, as the radius of earth decreases or the earth shrinks in size, the value of $g$ increases.
$g=\frac{G M}{R^{2}}$
As, mass remains constant.
$\Rightarrow \quad g \propto \frac{1}{R^{2}}$
so, as the radius of earth decreases or the earth shrinks in size, the value of $g$ increases.
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