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Question: Answered & Verified by Expert
If the focus of a hyperbola is (±3,0) and the equation of a tangent is 2x+y-4=0, then the equation of the hyperbola is
MathematicsHyperbolaJEE Main
Options:
  • A 4x2-5y2=20
  • B 5x2-4y2=20
  • C 4x2-5y2=1
  • D 5x2-4y2=1
Solution:
2522 Upvotes Verified Answer
The correct answer is: 4x2-5y2=20
Given, ±ae, 0=±3, 0

  ae=3

 a2e2=9 

 b2+a2=9 ...(i)

 2x+y-4=0

   y=-2x+4

is the tangent to the hyperbola

  42=a2-22-b2 c2=a2m2-b2

  4a2-b2=16 ...(ii)

On solving Eqs. (i) and (ii), we get,

a2=5, b2=4 

Equation of hyperbola is x25y24 =1

 4x2-5y2=20

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