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If the input voltage $V_{i}$ to the circuit below is given by $V_{i}(t)=A \cos (2 \pi f t)$, the output voltage is given by $\mathrm{V}_{\mathrm{o}}(\mathrm{t})=\mathrm{B} \cos (2 \pi \mathrm{ft}+\phi)$
Which one of the following four graphs best depict the variation of $\phi$ vs $f$ ?
Options:
Which one of the following four graphs best depict the variation of $\phi$ vs $f$ ?
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Resultant of $V_{C}, V_{R} \& B$ give $V_{i}$ and angle between $V_{i} \& B$ is $\phi .$ When $f$ is very high $X_{C} \rightarrow O$ then $\mathrm{V}_{\mathrm{C}} \rightarrow \mathrm{O} \therefore$ Resultant of $\mathrm{V}_{\mathrm{C}}, \mathrm{V}_{\mathrm{R}} \& \mathrm{~B}$ lie between $\mathrm{B}$ and $\mathrm{V}_{\mathrm{R}}$
B lag behind $\phi$
$\therefore$ At higher frequency $\phi$ become - ve.
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