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If the letters of the word ALGORITHM are arranged a random in a row what is the probability the letters GOR must remain together as a unit?
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So, If we take GOR as one letter then the No. of favourable cases is 7 !
Required probability $=\frac{7 !}{9 !}=\frac{7 !}{(9)(8) 7 !}=\frac{1}{72}$
Required probability $=\frac{7 !}{9 !}=\frac{7 !}{(9)(8) 7 !}=\frac{1}{72}$
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