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If the line $p x-q y=r$ intersects the coordinate axes at $(a, 0)$ and $(0, b)$, then the value of $(a+b)$ is equal to
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Verified Answer
The correct answer is:
$\frac{r(q-p)}{p q}$
We have,
$p x-q y=r$ intersect the coordinates axes at $(a, 0)$
and $(0, b)$.
$\therefore \quad p a=r \Rightarrow a=\frac{r}{p}$
$0-b q=r \Rightarrow b=\frac{-r}{q}$
$\therefore \quad a+b=\frac{r}{p}-\frac{r}{q}=\frac{r(q-p)}{p q}$
$p x-q y=r$ intersect the coordinates axes at $(a, 0)$
and $(0, b)$.
$\therefore \quad p a=r \Rightarrow a=\frac{r}{p}$
$0-b q=r \Rightarrow b=\frac{-r}{q}$
$\therefore \quad a+b=\frac{r}{p}-\frac{r}{q}=\frac{r(q-p)}{p q}$
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