If the mass of neutron = 1.7 × 10 - 27 kg , then the de-Broglie wavelength of neutron of energy 3 eV is ( h = 6.6 × 10 - 34 J - s )

Question

If the mass of neutron = 1.7 × 10 - 27 kg , then the de-Broglie wavelength of neutron of energy 3 eV is ( h = 6.6 × 10 - 34 J - s ), 1.6 × 10 - 16 m, 1.6 × 10 - 11 m, 1.4 × 10 - 10 m, 1.4 × 10 - 11 m

MARKS App · Accepted Answer

Given E = 3 e V = 3 × 1.6 × 10 - 19 J We know that λ = h 2 m E = 6.6 × 10 - 34 2 × 1.7 × 10 - 27 × 3 × 1.6 × 10 - 19 = 1.65 × 10 - 11 m

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