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If the parabola $y^2=4 a x$ passes through $(-3,2)$, then length of its latus rectum is
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The correct answer is:
$4 / 3$
The point $(-3,2)$ will satisfy the equation $y^2=4 a x$
$\Rightarrow 4=-12 a \Rightarrow 4 a=-\frac{4}{3}=\frac{4}{3}, \quad$ (Taking positive sign).
$\Rightarrow 4=-12 a \Rightarrow 4 a=-\frac{4}{3}=\frac{4}{3}, \quad$ (Taking positive sign).
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